Equivalent circuit of the
induction machine (per
unit)
fs = (Lm
+ Lsl)Is + Lm Ir
fr = Lm
Is + (Lm + Lrl)Ir
Vs = Rs
Is + jws
fs
0 = Rr Ir + j(ws-wm) fr
Te = k Im[fs* Is] = k Im[Ir* fr]
= k |Ir|2 Rr / (ws-wm)
k = 1 (pu)
= 3 poles / 4 (SI)